• 1903 Occurrence

    Time Limit : 2000/1000 MS(Java/Others) | Memory Limit : 131072/65536 KB(Java/Others)

    Submits : 132 | Solved : 66

    Description

    Given a string A which can be represented as A1A2..An (n is the length of A) and a string B which can be represented as B1B2..Bm (m is the length of B), you will need to find the occurrence of B from A.
    
    The definition of occurrence is as follows:
    If there exists an index p (p >= 1 and p + m <= n), and ApAp+1..Ap+m-1 matches with any rotation of B (B1B2..Bm-1Bm, B2B3..BmB1, …, BmB1..Bm-2Bm-1 are all the rotation of B), we call it is an occurrence of B from A.
    
    

    Input

    This problem contains multiple test cases. Each test case contains two lines, which are the strings A and B. The length of A is not greater then 1000 and the length of B is not greater than 100. All the strings are only consist of lowercase letters.

    Output

    Each test should output an integer indicating the occurrence of B from A in a single line.
    

    Sample Input

    abab
    ab
    aaaa
    a
    aaaa
    aa
    

    Sample Output

    3
    4
    3
    

    HINT


    Source

    Zhejiang Provincial Programming Contest 2006, Preliminary

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